2^5.5=4x^2

Solution for 2^5.5=4x^2 equation:

2^5.5=4x^2

We move all terms to the left:

2^5.5-(4x^2)=0

We add all the numbers together, and all the variables

-4x^2+45.2548339959=0

a = -4; b = 0; c = +45.2548339959;
Δ = b2-4ac
Δ = 02-4·(-4)·45.2548339959
Δ = 724.077343934
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{724.077343934}}{2*-4}=\frac{0-\sqrt{724.077343934}}{-8}
=-\frac{\sqrt{}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{724.077343934}}{2*-4}=\frac{0+\sqrt{724.077343934}}{-8}
=\frac{\sqrt{}}{-8}
$